How to check if a number is palindrome or not? (Python)

Here i'am going to take two examples one is the basic method (long and general) and other in which i will use some inbuilt function of python to make the program a lot easier.

1st method

1. Here , the idea is to break the digits of a number and place them in their revered order by multiplying 1 with last digit and adding 10*2nd last digit and again adding 100*3rd last digit and so on till we reach to first digit.
2. after getting the reverse of a number we have to check that it is equal to the original number.

if __name__ == '__main__':
    num = int(input())
    rem = rev = 0
    temp = num
    while num != 0:
        rem = num % 10
        rev = rev * 10 + rem
        num //= 10
    if temp == rev:
        print("palindrome")
    else:
        print("not palindrome")

2nd method

In this method, reversed() built in function will be used to reverse the given number and check if the number is palindrome or not.

1. take input in integer form
2. convert it into list
3. check if the number is same as in the reversed form
4. if yes print "palindrome" else print "not palindrome".

if __name__=='__main__':
    num=int(input())
    num=[int(i) for i in str(num)]
    if num == list(reversed(num)):
        print("palindrome")
    else:
        print("not palindrome")

we can also implement this as a user defined function isPalindrome() : it will return true if number is palindrome or false if not palindrome.

def ispalindrome(num):
    num = [int(i) for i in str(num)]
    if num == list(reversed(num)):
        return True
    else:
        return False


if __name__ == '__main__':
    num = int(input())
    if ispalindrome(num):
        print("palindrome")
    else:
        print("not palindrome")

if any doubts or queries please comment :)